To solve the equation \( 5(2x - 1) = 8x + 1 \), follow these steps:
Distribute the \( 5 \) on the left side: \[ 5 \cdot 2x - 5 \cdot 1 = 10x - 5 \] So, the equation becomes: \[ 10x - 5 = 8x + 1 \]
Next, isolate \( x \) by subtracting \( 8x \) from both sides: \[ 10x - 8x - 5 = 1 \] This simplifies to: \[ 2x - 5 = 1 \]
Now, add \( 5 \) to both sides: \[ 2x = 1 + 5 \] This gives: \[ 2x = 6 \]
Finally, divide by \( 2 \) to solve for \( x \): \[ x = \frac{6}{2} = 3 \]
So, the solution is: \[ x = 3 \]