-8(11-2а)+40=3(5а-4)

To solve the equation \(-8(11 - 2a) + 40 = 3(5a - 4)\), we can follow these steps:

1. Distribute the -8 on the left side: \[ -8 \cdot 11 + (-8) \cdot (-2a) + 40 = 3(5a - 4) \] \[ -88 + 16a + 40 = 3(5a - 4) \]

2. Combine like terms on the left side: \[ (16a - 48) = 3(5a - 4) \]

3. Distribute the 3 on the right side: \[ 16a - 48 = 15a - 12 \]

4. To isolate \(a\), subtract \(15a\) from both sides: \[ 16a - 15a - 48 = -12 \] \[ a - 48 = -12 \]

5. Now, add 48 to both sides to solve for \(a\): \[ a = -12 + 48 \] \[ a = 36 \]

Thus, the solution to the equation is: \[ a = 36 \]