Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №2645047
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Аноним
19 января 2025 18:21 · публичный вопрос
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Аноним

x ^ 2 + 8x = 0 5x ^ 2 - x = 0 6y ^ 2 - 30y = 0 3x ^ 2 - 1, 2x = 0 6х2-0,5х=0 1/4 * y ^ 2 + y = 0 x - 10x ^ 2 = 0 6x-0,2x²-0

Ответ нейросети
19 января 2025 18:21

Let's solve each equation step by step.

  1. Equation: \( x^2 + 8x = 0 \)

    Factoring: \[ x(x + 8) = 0 \]

    Solution: \[ x = 0 \quad \text{or} \quad x + 8 = 0 \Rightarrow x = -8 \]

    Roots: \( x = 0, -8 \)

  2. Equation: \( 5x^2 - x = 0 \)

    Factoring: \[ x(5x - 1) = 0 \]

    Solution: \[ x = 0 \quad \text{or} \quad 5x - 1 = 0 \Rightarrow x = \frac{1}{5} \]

    Roots: \( x = 0, \frac{1}{5} \)

  3. Equation: \( 6y^2 - 30y = 0 \)

    Factoring: \[ 6y(y - 5) = 0 \]

    Solution: \[ y = 0 \quad \text{or} \quad y - 5 = 0 \Rightarrow y = 5 \]

    Roots: \( y = 0, 5 \)

  4. Equation: \( 3x^2 - 1, 2x = 0 \) (assuming you intended to write \( 3x^2 - 1 + 2x = 0 \))

    Rearranging: \[ 3x^2 + 2x - 1 = 0 \]

    Using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 3 \cdot (-1)}}{2 \cdot 3} \] \[ = \frac{-2 \pm \sqrt{4 + 12}}{6} = \frac{-2 \pm \sqrt{16}}{6} = \frac{-2 \pm 4}{6} \]

    Solutions: \[ x = \frac{2}{6} = \frac{1}{3} \quad \text{and} \quad x = \frac{-6}{6} = -1 \]

    Roots: \( x = \frac{1}{3}, -1 \)

  5. Equation: \( 6x^2 - 0.5x = 0 \)

    Factoring: \[ x(6x - 0.5) = 0 \]

    Solution: \[ x = 0 \quad \text{or} \quad 6x - 0.5 = 0 \Rightarrow x = \frac{0.5}{6} = \frac{1}{12} \]

    Roots: \( x = 0, \frac{1}{12} \)

  6. Equation: \( \frac{1}{4} y^2 + y = 0 \)

    Factoring: \[ y(\frac{1}{4} y + 1) = 0 \]

    Solution: \[ y = 0 \quad \text{or} \quad \frac{1}{4} y + 1 = 0 \Rightarrow y = -4 \]

    Roots: \( y = 0, -4 \)

  7. Equation: \( x - 10x^2 = 0 \)

    Factoring: \[ x(1 - 10x) = 0 \]

    Solution: \[ x = 0 \quad \text{or} \quad 1 - 10x = 0 \Rightarrow x = \frac{1}{10} \]

    Roots: \( x = 0, \frac{1}{10} \)

  8. Equation: \( 6x - 0.2x^2 = 0 \)

    Factoring: \[ x(6 - 0.2x) = 0 \]

    Solution: \[ x = 0 \quad \text{or} \quad 6 - 0.2x = 0 \Rightarrow 0.2x = 6 \Rightarrow x = \frac{6}{0.2} = 30 \]

    Roots: \( x = 0, 30 \)

Summary of Roots:

  1. \( x = 0, -8 \)
  2. \( x = 0, \frac{1}{5} \)
  3. \( y = 0, 5 \)
  4. \( x = \frac{1}{3}, -1 \)
  5. \( x = 0, \frac{1}{12} \)
  6. \( y = 0, -4 \)
  7. \( x = 0, \frac{1}{10} \)
  8. \( x = 0, 30 \)