Let's solve each equation step by step.
Equation: \( x^2 + 8x = 0 \)
Factoring: \[ x(x + 8) = 0 \]
Solution: \[ x = 0 \quad \text{or} \quad x + 8 = 0 \Rightarrow x = -8 \]
Roots: \( x = 0, -8 \)
Equation: \( 5x^2 - x = 0 \)
Factoring: \[ x(5x - 1) = 0 \]
Solution: \[ x = 0 \quad \text{or} \quad 5x - 1 = 0 \Rightarrow x = \frac{1}{5} \]
Roots: \( x = 0, \frac{1}{5} \)
Equation: \( 6y^2 - 30y = 0 \)
Factoring: \[ 6y(y - 5) = 0 \]
Solution: \[ y = 0 \quad \text{or} \quad y - 5 = 0 \Rightarrow y = 5 \]
Roots: \( y = 0, 5 \)
Equation: \( 3x^2 - 1, 2x = 0 \) (assuming you intended to write \( 3x^2 - 1 + 2x = 0 \))
Rearranging: \[ 3x^2 + 2x - 1 = 0 \]
Using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 3 \cdot (-1)}}{2 \cdot 3} \] \[ = \frac{-2 \pm \sqrt{4 + 12}}{6} = \frac{-2 \pm \sqrt{16}}{6} = \frac{-2 \pm 4}{6} \]
Solutions: \[ x = \frac{2}{6} = \frac{1}{3} \quad \text{and} \quad x = \frac{-6}{6} = -1 \]
Roots: \( x = \frac{1}{3}, -1 \)
Equation: \( 6x^2 - 0.5x = 0 \)
Factoring: \[ x(6x - 0.5) = 0 \]
Solution: \[ x = 0 \quad \text{or} \quad 6x - 0.5 = 0 \Rightarrow x = \frac{0.5}{6} = \frac{1}{12} \]
Roots: \( x = 0, \frac{1}{12} \)
Equation: \( \frac{1}{4} y^2 + y = 0 \)
Factoring: \[ y(\frac{1}{4} y + 1) = 0 \]
Solution: \[ y = 0 \quad \text{or} \quad \frac{1}{4} y + 1 = 0 \Rightarrow y = -4 \]
Roots: \( y = 0, -4 \)
Equation: \( x - 10x^2 = 0 \)
Factoring: \[ x(1 - 10x) = 0 \]
Solution: \[ x = 0 \quad \text{or} \quad 1 - 10x = 0 \Rightarrow x = \frac{1}{10} \]
Roots: \( x = 0, \frac{1}{10} \)
Equation: \( 6x - 0.2x^2 = 0 \)
Factoring: \[ x(6 - 0.2x) = 0 \]
Solution: \[ x = 0 \quad \text{or} \quad 6 - 0.2x = 0 \Rightarrow 0.2x = 6 \Rightarrow x = \frac{6}{0.2} = 30 \]
Roots: \( x = 0, 30 \)
Summary of Roots:
- \( x = 0, -8 \)
- \( x = 0, \frac{1}{5} \)
- \( y = 0, 5 \)
- \( x = \frac{1}{3}, -1 \)
- \( x = 0, \frac{1}{12} \)
- \( y = 0, -4 \)
- \( x = 0, \frac{1}{10} \)
- \( x = 0, 30 \)