x2-3x+2=0 x1= x2=

To solve the quadratic equation \( x^2 - 3x + 2 = 0 \), we can factor the equation.

We look for two numbers that multiply to 2 (the constant term) and add to -3 (the coefficient of \( x \)). The numbers -1 and -2 fulfill these conditions:

\[ (x - 1)(x - 2) = 0 \]

Setting each factor equal to zero gives us the solutions:

1. \( x - 1 = 0 \) → \( x_1 = 1 \)
2. \( x - 2 = 0 \) → \( x_2 = 2 \)

Thus, the solutions are: \[ x_1 = 1, \quad x_2 = 2 \]