x2-6,4x+2,5=0 x1+x2= x1•x2=

To solve the quadratic equation \(x^2 - 6.4x + 2.5 = 0\), we can use Vieta's formulas. According to Vieta's formulas, for a quadratic equation of the form \(ax^2 + bx + c = 0\):

1. The sum of the roots \(x_1 + x_2 = -\frac{b}{a}\)
2. The product of the roots \(x_1 \cdot x_2 = \frac{c}{a}\)

In this case, we have:

• \(a = 1\)
• \(b = -6.4\)
• \(c = 2.5\)

Now, using Vieta's formulas:

1. Sum of the roots: \[ x_1 + x_2 = -\frac{-6.4}{1} = 6.4 \]

2. Product of the roots: \[ x_1 \cdot x_2 = \frac{2.5}{1} = 2.5 \]

So, the values are:

• \(x_1 + x_2 = 6.4\)
• \(x_1 \cdot x_2 = 2.5\)