X2-6,4x+2,5=0 x1+x2= x1•x2=

To solve the quadratic equation \(x^2 - 6.4x + 2.5 = 0\), we can use Vieta's formulas. According to Vieta's formulas, for a quadratic equation of the form \(ax^2 + bx + c = 0\): 1. The sum of the roots \(x_1 + x_2 = -\frac{b}{a}\) 2. The product of the roots \(x_1 \cdot x_2 = \frac{c}{a}\) In this case, we have: - \(a = 1\) - \(b = -6.4\) - \(c = 2.5\) Now, using Vieta's formulas: 1. **Sum of the roots**: \[ x_1 + x_2 = -\frac{-6.4}{1} = 6.4 \] 2. **Product of the roots**: \[ x_1 \cdot x_2 = \frac{2.5}{1} = 2.5 \] So, the values are: - \(x_1 + x_2 = 6.4\) - \(x_1 \cdot x_2 = 2.5\)