Mn^3-n

The expression \( mn^3 - n \) can be factored. We can see that \( n \) is a common factor in both terms: \[ mn^3 - n = n(mn^2 - 1) \] Next, we can recognize that \( mn^2 - 1 \) can be factored further, as it is a difference of squares: \[ mn^2 - 1 = (mn - 1)(mn + 1) \] Putting it all together, the complete factorization of the original expression is: \[ mn^3 - n = n(mn - 1)(mn + 1) \] This provides a clearer form of the original expression, making it easier to analyze or solve if needed. If you have a specific context or additional questions regarding this expression, please let me know!