49x2-1=0

The equation given is: \[ 49x^2 - 1 = 0 \] This is a difference of squares, which can be factored as: \[ (7x - 1)(7x + 1) = 0 \] Setting each factor to zero gives: 1. \( 7x - 1 = 0 \) leads to \( x = \frac{1}{7} \) 2. \( 7x + 1 = 0 \) leads to \( x = -\frac{1}{7} \) So, the solutions are \( x = \frac{1}{7} \) and \( x = -\frac{1}{7} \).