(4+х)(x-4)

To expand the expression \((4+x)(x-4)\), you use the distributive property (also known as the FOIL method for binomials). Here's how it goes: \[ (4+x)(x-4) = 4 \cdot x + 4 \cdot (-4) + x \cdot x + x \cdot (-4) \] Now, calculate each term: 1. \(4 \cdot x = 4x\) 2. \(4 \cdot (-4) = -16\) 3. \(x \cdot x = x^2\) 4. \(x \cdot (-4) = -4x\) Now, combine the like terms: \[ 4x - 4x + x^2 - 16 \] The \(4x\) and \(-4x\) cancel each other out, leaving you with: \[ x^2 - 16 \] So, the expanded form of the expression \((4+x)(x-4)\) is: \[ x^2 - 16 \] This can also be recognized as a difference of squares, which can be factored further into \((x-4)(x+4)\) if needed.