To solve the quadratic equation \( x^2 - 5x + 6 = 0 \), we can factor it.
We need to find two numbers that multiply to 6 (the constant term) and add up to -5 (the coefficient of x).
The numbers that meet these criteria are -2 and -3 since:
- \(-2 \times -3 = 6\)
- \(-2 + -3 = -5\)
Now, we can factor the quadratic: \[ (x - 2)(x - 3) = 0 \]
Setting each factor equal to zero gives us: \[ x - 2 = 0 \quad \text{or} \quad x - 3 = 0 \]
Solving these equations, we find: \[ x = 2 \quad \text{and} \quad x = 3 \]
Thus, the solutions to the equation \( x^2 - 5x + 6 = 0 \) are \( x = 2 \) and \( x = 3 \).