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Вопрос от Анонимного юзера 21 января 2025 17:23

1/4sinx

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21 января 2025 17:23

The expression ( \frac{1}{4} \sin x ) represents a scaled version of the sine function.

Here are a few properties and transformations related to this expression:

  1. Amplitude: The amplitude of the function ( \frac{1}{4} \sin x ) is ( \frac{1}{4} ). This means that the maximum value of ( \sin x ), which is 1, will now only reach ( \frac{1}{4} ).

  2. Period: The period of ( \sin x ) is ( 2\pi ). The period does not change with the scaling factor, so the period of ( \frac{1}{4} \sin x ) is still ( 2\pi ).

  3. Graph: When you graph ( y = \frac{1}{4} \sin x ), the wave will oscillate between ( -\frac{1}{4} ) and ( \frac{1}{4} ) along the y-axis.

  4. Value at specific points:

    • ( x = 0 ): ( \frac{1}{4} \sin(0) = 0 )
    • ( x = \frac{\pi}{2} ): ( \frac{1}{4} \sin\left(\frac{\pi}{2}\right) = \frac{1}{4} )
    • ( x = \pi ): ( \frac{1}{4} \sin(\pi) = 0 )
    • ( x = \frac{3\pi}{2} ): ( \frac{1}{4} \sin\left(\frac{3\pi}{2}\right) = -\frac{1}{4} )
    • ( x = 2\pi ): ( \frac{1}{4} \sin(2\pi) = 0 )

If you need further analysis or applications of this expression, such as derivatives, integrals, or specific equations, feel free to ask!

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1/4sinx
The expression \( \frac{1}{4} \sin x \) represents a scaled version of the sine function. Here are a few properties and transformations related to this expression: 1. **Amplitude**: The amplitude of the function \( \frac{1}{4} \sin x \) is \( \frac{1}{4} \). This means that the maximum value of \( \sin x \), which is 1, will now only reach \( \frac{1}{4} \). 2. **Period**: The period of \( \sin x \) is \( 2\pi \). The period does not change with the scaling factor, so the period of \( \frac{1}{4} \sin x \) is still \( 2\pi \). 3. **Graph**: When you graph \( y = \frac{1}{4} \sin x \), the wave will oscillate between \( -\frac{1}{4} \) and \( \frac{1}{4} \) along the y-axis. 4. **Value at specific points**: - \( x = 0 \): \( \frac{1}{4} \sin(0) = 0 \) - \( x = \frac{\pi}{2} \): \( \frac{1}{4} \sin\left(\frac{\pi}{2}\right) = \frac{1}{4} \) - \( x = \pi \): \( \frac{1}{4} \sin(\pi) = 0 \) - \( x = \frac{3\pi}{2} \): \( \frac{1}{4} \sin\left(\frac{3\pi}{2}\right) = -\frac{1}{4} \) - \( x = 2\pi \): \( \frac{1}{4} \sin(2\pi) = 0 \) If you need further analysis or applications of this expression, such as derivatives, integrals, or specific equations, feel free to ask!