To simplify the expression \((5y^2 - 3y - 1) + (8y^2 + 2y - 11)\), you can combine like terms.
Combine the \(y^2\) terms: \[ 5y^2 + 8y^2 = 13y^2 \]
Combine the \(y\) terms: \[ -3y + 2y = -1y \quad \text{or simply} \quad -y \]
Combine the constant terms: \[ -1 - 11 = -12 \]
Now, putting it all together, you have: \[ 13y^2 - y - 12 \]
Thus, the simplified expression is: \[ 13y^2 - y - 12 \]