{х-2у=-9/у=3х+2

You have a system of equations: 1. \( x - 2y = -9 \) 2. \( y = 3x + 2 \) Let's solve this system of equations step-by-step. Substituting equation (2) into equation (1): 1. \( x - 2(3x + 2) = -9 \) Now simplify: 1. \( x - 6x - 4 = -9 \) 2. Combine like terms: \[ -5x - 4 = -9 \] 3. Add 4 to both sides: \[ -5x = -5 \] 4. Divide by -5: \[ x = 1 \] Now, substitute \( x = 1 \) back into equation (2) to find \( y \): \[ y = 3(1) + 2 \] \[ y = 3 + 2 \] \[ y = 5 \] Thus, the solution to the system of equations is: \[ x = 1, \quad y = 5 \] The solution can be written as the ordered pair \( (1, 5) \).