KOH+FESo4

When potassium hydroxide (KOH) reacts with iron(II) sulfate (FeSO₄), a double displacement reaction occurs. The products of this reaction are potassium sulfate (K₂SO₄) and iron(II) hydroxide (Fe(OH)₂).

The balanced chemical equation for this reaction is:

\[ 2 \text{KOH} + \text{FeSO}_4 \rightarrow \text{K}_2\text{SO}_4 + \text{Fe(OH)}_2 \]

In this reaction:

• KOH provides potassium ions (K⁺) and hydroxide ions (OH⁻).
• FeSO₄ provides iron(II) ions (Fe²⁺) and sulfate ions (SO₄²⁻).

Please note that Fe(OH)₂ is a precipitate and may appear as a greenish solid in the reaction mixture.