-9(8-9x)=4x+5

To solve the equation \(-9(8-9x) = 4x + 5\), we start by distributing \(-9\) on the left side.

1. Distribute \(-9\): \[ -9 \cdot 8 + 9 \cdot 9x = -72 + 81x \] So, the equation becomes: \[ -72 + 81x = 4x + 5 \]

2. Next, we want to get all the \(x\) terms on one side and the constant terms on the other side. Subtract \(4x\) from both sides: \[ -72 + 81x - 4x = 5 \] This simplifies to: \[ -72 + 77x = 5 \]

3. Next, add \(72\) to both sides: \[ 77x = 5 + 72 \] \[ 77x = 77 \]

4. Now, divide both sides by \(77\): \[ x = \frac{77}{77} \] \[ x = 1 \]

Thus, the solution to the equation is: \[ \boxed{1} \]