x2 ——— = 3x ——— 2-x 2-x

To solve the equation

\[ \frac{x^2}{3x} = \frac{2-x}{2-x} \]

we first simplify each side.

1. The right side simplifies to 1, as long as \(2 - x \neq 0\) (i.e., \(x \neq 2\)).

2. The left side simplifies as follows:

   \[ \frac{x^2}{3x} = \frac{x}{3} \quad \text{(assuming \(x \neq 0\))} \]

So we rewrite the equation as:

\[ \frac{x}{3} = 1 \]

Next, multiply both sides by 3:

\[ x = 3 \]

Now we check the conditions we assumed earlier:

• \(x \neq 0\) \(\Rightarrow\) \(x = 3\) satisfies this.
• \(x \neq 2\) \(\Rightarrow\) \(x = 3\) satisfies this as well.

Thus, the solution to the equation is:

\[ \boxed{3} \]