(x-29)(-25x-5)=0

To solve the equation \((x - 29)(-25x - 5) = 0\), we can set each factor equal to zero and solve for \(x\).

1. Set the first factor equal to zero: \[ x - 29 = 0 \] Solving for \(x\): \[ x = 29 \]

2. Set the second factor equal to zero: \[ -25x - 5 = 0 \] Solving for \(x\): \[ -25x = 5 \\ x = -\frac{5}{25} \\ x = -\frac{1}{5} \]

Thus, the solutions to the equation \((x - 29)(-25x - 5) = 0\) are: \[ x = 29 \quad \text{and} \quad x = -\frac{1}{5} \]