(1×⅚+⅗)×24

To solve the expression \((1 \times \frac{5}{6} + \frac{3}{5}) \times 24\), we start with simplifying the expression inside the parentheses: 1. We first calculate \(1 \times \frac{5}{6}\): \[ 1 \times \frac{5}{6} = \frac{5}{6} \] 2. Next, we need to add \(\frac{5}{6}\) and \(\frac{3}{5}\). To do this, we need a common denominator. The least common multiple of 6 and 5 is 30. - Convert \(\frac{5}{6}\) to have a denominator of 30: \[ \frac{5}{6} = \frac{5 \times 5}{6 \times 5} = \frac{25}{30} \] - Convert \(\frac{3}{5}\) to have a denominator of 30: \[ \frac{3}{5} = \frac{3 \times 6}{5 \times 6} = \frac{18}{30} \] 3. Now we can add the fractions: \[ \frac{25}{30} + \frac{18}{30} = \frac{25 + 18}{30} = \frac{43}{30} \] 4. Now we need to multiply this result by 24: \[ \left(\frac{43}{30}\right) \times 24 \] We can simplify this: \[ = \frac{43 \times 24}{30} \] 5. Calculate \(43 \times 24\): \[ 43 \times 24 = 1032 \] 6. Now simplify \(\frac{1032}{30}\) by dividing both the numerator and denominator by 6: \[ \frac{1032 \div 6}{30 \div 6} = \frac{172}{5} \] So, the final answer is: \[ \frac{172}{5} \quad \text{or} \quad 34.4 \]