3(х+1)-9=6(х+2)

Let's solve the equation step by step:

Given: \[ 3(x + 1) - 9 = 6(x + 2) \]

1. Distribute the 3 on the left side: \[ 3x + 3 - 9 = 6(x + 2) \]

2. Simplify the left side: \[ 3x - 6 = 6(x + 2) \]

3. Distribute the 6 on the right side: \[ 3x - 6 = 6x + 12 \]

4. Now, we can move all terms involving \( x \) to one side and constant terms to the other side. Let's move \( 6x \) to the left and \( -6 \) to the right: \[ 3x - 6x = 12 + 6 \]

5. Combine like terms: \[ -3x = 18 \]

6. Divide both sides by -3: \[ x = -6 \]

So, the solution is: \[ x = -6 \]