7(8z-10)-25(4z+3)=3(5z-z=

To solve the equation \( 7(8z-10)-25(4z+3)=3(5z-z) \), let's first simplify both sides. 1. Start with the left side: \[ 7(8z - 10) - 25(4z + 3) \] Distribute the terms: \[ = 56z - 70 - 100z - 75 \] Combine like terms: \[ = (56z - 100z) + (-70 - 75) = -44z - 145 \] 2. Now simplify the right side: \[ 3(5z - z) \] Combine the terms inside the parentheses: \[ = 3(4z) = 12z \] Now the equation looks like this: \[ -44z - 145 = 12z \] 3. Next, let's move the terms involving \( z \) to one side. Add \( 44z \) to both sides: \[ -145 = 12z + 44z \] This simplifies to: \[ -145 = 56z \] 4. Now, solve for \( z \) by dividing both sides by 56: \[ z = \frac{-145}{56} \] 5. Finally, let's simplify the fraction (if needed): \[ z = -\frac{145}{56} \] Therefore, the solution is: \[ z = -\frac{145}{56} \]