7(8z-10)-25(4z+3)=3(5z-z=

To solve the equation \( 7(8z-10)-25(4z+3)=3(5z-z) \), let's first simplify both sides.

1. Start with the left side:

\[ 7(8z - 10) - 25(4z + 3) \]

Distribute the terms:

\[ = 56z - 70 - 100z - 75 \]

Combine like terms:

\[ = (56z - 100z) + (-70 - 75) = -44z - 145 \]

2. Now simplify the right side:

\[ 3(5z - z) \]

Combine the terms inside the parentheses:

\[ = 3(4z) = 12z \]

Now the equation looks like this:

\[ -44z - 145 = 12z \]

3. Next, let's move the terms involving \( z \) to one side. Add \( 44z \) to both sides:

\[ -145 = 12z + 44z \]

This simplifies to:

\[ -145 = 56z \]

4. Now, solve for \( z \) by dividing both sides by 56:

\[ z = \frac{-145}{56} \]

5. Finally, let's simplify the fraction (if needed):

\[ z = -\frac{145}{56} \]

Therefore, the solution is:

\[ z = -\frac{145}{56} \]