12 sin 60° * cos 60°

To solve \( 12 \sin 60^\circ \cdot \cos 60^\circ \), we first need to know the values of \( \sin 60^\circ \) and \( \cos 60^\circ \). - \( \sin 60^\circ = \frac{\sqrt{3}}{2} \) - \( \cos 60^\circ = \frac{1}{2} \) Now, substitute these values into the expression: \[ 12 \sin 60^\circ \cdot \cos 60^\circ = 12 \left( \frac{\sqrt{3}}{2} \right) \cdot \left( \frac{1}{2} \right) \] \[ = 12 \cdot \frac{\sqrt{3}}{2} \cdot \frac{1}{2} = 12 \cdot \frac{\sqrt{3}}{4} \] \[ = 3 \sqrt{3} \] Thus, \( 12 \sin 60^\circ \cdot \cos 60^\circ = 3 \sqrt{3} \).