2х + 0•y =14 X=7 Y=3

Let's analyze the equation and the values provided:

The equation is: \[ 2x + 0 \cdot y = 14 \]

Since \(0 \cdot y\) equals 0 for any value of \(y\), the equation simplifies to: \[ 2x = 14 \]

To solve for \(x\): \[ x = \frac{14}{2} = 7 \]

You've also provided:

• \( x = 7 \)
• \( y = 3 \)

Since \(x = 7\) satisfies the equation \(2x = 14\), this part is correct.

The value of \(y\) does not affect the outcome of the equation because it is multiplied by 0. Thus, any value of \(y\) is valid.

In conclusion:

• The solution \(x = 7\) is correct.
• Any value of \(y\) including \(y = 3\) is acceptable.

If you have further questions or need clarification on a specific topic, feel free to ask!