m=5кг t1=230 t2=120 c=230 кг/дж Q=?

To calculate the heat transfer (Q), you can use the formula:

\[ Q = mc(t_2 - t_1) \]

where:

• \( m \) is the mass in kg,
• \( c \) is the specific heat capacity in kg/J,
• \( t_1 \) and \( t_2 \) are the initial and final temperatures in degrees Celsius or Kelvin, respectively.

Given:

• \( m = 5 \, \text{kg} \)
• \( t_1 = 230 \, \text{°C} \)
• \( t_2 = 120 \, \text{°C} \)
• \( c = 230 \, \text{kg/J} \)

Now substituting in the values:

\[ Q = 5 \, \text{kg} \times 230 \, \text{kg/J} \times (120 - 230) \]

Calculating the change in temperature:

\[ t_2 - t_1 = 120 - 230 = -110 \, \text{°C} \]

Now substitute that into the equation for Q:

\[ Q = 5 \, \text{kg} \times 230 \, \text{kg/J} \times (-110 \, \text{°C}) \]

Calculating Q:

\[ Q = 5 \times 230 \times (-110) \]

\[ Q = 5 \times 230 = 1150 \]

\[ 1150 \times (-110) = -126500 \, \text{J} \]

So,

\[ Q = -126500 \, \text{J} \]

The negative sign indicates that heat is being released (or lost) by the substance.