To multiply the mixed numbers \(6 \frac{1}{4}\) and \(-1 \frac{3}{5}\), we first convert them into improper fractions.
Convert \(6 \frac{1}{4}\): \[ 6 \frac{1}{4} = 6 \times 4 + 1 = 24 + 1 = 25 \quad \text{so it becomes} \quad \frac{25}{4} \]
Convert \(-1 \frac{3}{5}\): \[ -1 \frac{3}{5} = -\left(1 \times 5 + 3\right) = -\left(5 + 3\right) = -8 \quad \text{so it becomes} \quad -\frac{8}{5} \]
Now we multiply the improper fractions: \[ \frac{25}{4} \times -\frac{8}{5} \]
Multiply the numerators and the denominators: \[ = \frac{25 \times -8}{4 \times 5} = \frac{-200}{20} \]
Now simplify \(\frac{-200}{20}\): \[ = -10 \]
So, \(6 \frac{1}{4} \times (-1 \frac{3}{5}) = -10\).