6+х<3-2х

To solve the inequality \( 6 + x < 3 - 2x \), follow these steps: 1. **Add \( 2x \) to both sides** to get all terms involving \( x \) on one side: \[ 6 + x + 2x < 3 \] Which simplifies to: \[ 6 + 3x < 3 \] 2. **Subtract 6 from both sides** to isolate the term with \( x \): \[ 3x < 3 - 6 \] Simplifying this gives: \[ 3x < -3 \] 3. **Divide both sides by 3** to solve for \( x \): \[ x < -1 \] So, the solution to the inequality is: \[ x < -1 \]