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Вопрос от Анонимного юзера 04 марта 2025 08:40

G1=2*10^-9 кл g2=4*10^-9кл k=9*10^9H*m2/kl2 F=80*10^-3H r-?

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04 марта 2025 08:40

To find the distance ( r ) between the two charges ( g_1 ) and ( g_2 ), we can use Coulomb's Law, which states that the force ( F ) between two point charges is given by the formula:

[ F = k \cdot \frac{|g_1 \cdot g_2|}{r^2} ]

Where:

  • ( F ) is the force between the charges (given as ( 80 \times 10^{-3} ) N),
  • ( k ) is Coulomb's constant (given as ( 9 \times 10^9 , \text{N m}^2/\text{C}^2 )),
  • ( g_1 ) and ( g_2 ) are the charges (given as ( g_1 = 2 \times 10^{-9} , \text{C} ) and ( g_2 = 4 \times 10^{-9} , \text{C} )),
  • ( r ) is the distance between the charges (which we need to find).

Rearranging Coulomb's law to solve for ( r ):

[ r = \sqrt{k \cdot \frac{|g_1 \cdot g_2|}{F}} ]

Substituting the known values into the formula:

[ r = \sqrt{9 \times 10^9 \cdot \frac{|(2 \times 10^{-9}) \cdot (4 \times 10^{-9})|}{80 \times 10^{-3}}} ]

Calculating ( |(g_1 \cdot g_2)| ):

[ |g_1 \cdot g_2| = |(2 \times 10^{-9}) \cdot (4 \times 10^{-9})| = 8 \times 10^{-18} , \text{C}^2 ]

Now substituting this back into the equation for ( r ):

[ r = \sqrt{9 \times 10^9 \cdot \frac{8 \times 10^{-18}}{80 \times 10^{-3}}} ]

Calculating the fraction:

[ \frac{8 \times 10^{-18}}{80 \times 10^{-3}} = \frac{8}{80} \times 10^{-15} = 0.1 \times 10^{-15} = 1 \times 10^{-16} ]

Now substituting this back into our equation for ( r ):

[ r = \sqrt{9 \times 10^9 \cdot 1 \times 10^{-16}} = \sqrt{9 \times 10^{-7}} = 3 \times 10^{-4} , \text{m} ]

Thus, the distance ( r ) between the two charges is:

[ r = 3 \times 10^{-4} , \text{m} \quad \text{or} \quad 0.3 , \text{mm} ]

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g1=2*10^-9 кл g2=4*10^-9кл k=9*10^9H*m2/kl2 F=80*10^-3H r-?
To find the distance \( r \) between the two charges \( g_1 \) and \( g_2 \), we can use Coulomb's Law, which states that the force \( F \) between two point charges is given by the formula: \[ F = k \cdot \frac{|g_1 \cdot g_2|}{r^2} \] Where: - \( F \) is the force between the charges (given as \( 80 \times 10^{-3} \) N), - \( k \) is Coulomb's constant (given as \( 9 \times 10^9 \, \text{N m}^2/\text{C}^2 \)), - \( g_1 \) and \( g_2 \) are the charges (given as \( g_1 = 2 \times 10^{-9} \, \text{C} \) and \( g_2 = 4 \times 10^{-9} \, \text{C} \)), - \( r \) is the distance between the charges (which we need to find). Rearranging Coulomb's law to solve for \( r \): \[ r = \sqrt{k \cdot \frac{|g_1 \cdot g_2|}{F}} \] Substituting the known values into the formula: \[ r = \sqrt{9 \times 10^9 \cdot \frac{|(2 \times 10^{-9}) \cdot (4 \times 10^{-9})|}{80 \times 10^{-3}}} \] Calculating \( |(g_1 \cdot g_2)| \): \[ |g_1 \cdot g_2| = |(2 \times 10^{-9}) \cdot (4 \times 10^{-9})| = 8 \times 10^{-18} \, \text{C}^2 \] Now substituting this back into the equation for \( r \): \[ r = \sqrt{9 \times 10^9 \cdot \frac{8 \times 10^{-18}}{80 \times 10^{-3}}} \] Calculating the fraction: \[ \frac{8 \times 10^{-18}}{80 \times 10^{-3}} = \frac{8}{80} \times 10^{-15} = 0.1 \times 10^{-15} = 1 \times 10^{-16} \] Now substituting this back into our equation for \( r \): \[ r = \sqrt{9 \times 10^9 \cdot 1 \times 10^{-16}} = \sqrt{9 \times 10^{-7}} = 3 \times 10^{-4} \, \text{m} \] Thus, the distance \( r \) between the two charges is: \[ r = 3 \times 10^{-4} \, \text{m} \quad \text{or} \quad 0.3 \, \text{mm} \]