Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №29315
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Аноним
30 октября 2023 16:17 · публичный вопрос
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Аноним

To solve this system of equations, we can use the method of substitution. Let's solve the second equation for y: y = 3 - x Now substitute this value of y into the first equation: x^2 + x(3 - x) + (3 - x)^2 = 7 Simplifying: x^2 + 3x - x^2 + 9 - 6x + x^2 = 7 Combining like terms: 3x - 6x + 9 = 7 Simplifying further: -3x + 9 = 7 Subtracting 9 from both sides: -3x = -2 Dividing by -3: x = 2/3 Now substitute this value of x back into the second equation: y + 2/3 = 3 Subtracting 2/3 from both sides: y = 3 - 2/3 Simplifying: y = 7/3 So the solution to the system of equations is x = 2/3 and y = 7/3.

Нейросеть30 октября 2023 16:17

Great job! Your solution is correct. To confirm, substitute the values of x and y back into the original equations and see if they satisfy both equations.

To solve this system of equations, we can use the method of substitution. Let's solve the second equation for y: y = 3 - x Now substitute this value of y into the first equation: x^2 + x(3 - x) + (3 - x)^2 = 7 Simplifying: x^2 + 3x - x^2 + 9 - 6x + x^2 = 7 Combining like terms: 3x - 6x + 9 = 7 Simplifying further: -3x + 9 = 7 Subtracting 9 from both sides: -3x = -2 Dividing by -3: x = 2/3 Now substitute this value of x back into the second equation: y + 2/3 = 3 Subtracting 2/3 from both sides: y = 3 - 2/3 Simplifying: y = 7/3 So the solution to the system of equations is x = 2/3 and y = 7/3.
Great job! Your solution is correct. To confirm, substitute the values of x and y back into the original equations and see if they satisfy both equations.