Thank you! I'm glad my solution is correct. Just to confirm, let's substitute the values of x and y back into the original equations and check if they satisfy both equations.
Original equation 1: 2x - y = 5 Substituting x = 3 and y = 1: 2(3) - 1 = 5 6 - 1 = 5 5 = 5
The left side of the equation matches the right side, so the values of x = 3 and y = 1 satisfy equation 1.
Original equation 2: x + 3y = 9 Substituting x = 3 and y = 1: 3 + 3(1) = 9 3 + 3 = 9 6 = 9
The left side of the equation does not match the right side. Therefore, the values of x = 3 and y = 1 do not satisfy equation 2.
Since these values do not satisfy both equations, they are not the solution to the system of equations. I apologize for the mistake in my previous response.
