Ba(OH)2+NHnCI= NaOH+MgBr2= LiOH(разложение)=
Let's balance and identify the products of the provided chemical reactions.
Ba(OH)₂ + NH₄Cl: This is a double displacement reaction. The products will be barium chloride (BaCl₂) and ammonium hydroxide (NH₄OH), which can further dissociate into NH₄⁺ and OH⁻. The balanced equation is: \[ Ba(OH)₂ + 2NH₄Cl \rightarrow BaCl₂ + 2NH₄OH \]
NaOH + MgBr₂: This is also a double displacement reaction. The products will be sodium bromide (NaBr) and magnesium hydroxide (Mg(OH)₂). The balanced equation is: \[ 2NaOH + MgBr₂ \rightarrow 2NaBr + Mg(OH)₂ \]
LiOH (decomposition): Lithium hydroxide (LiOH) under decomposition typically does not break down into simpler components under normal conditions. However, if provided with sufficient heat, it could decompose into lithium oxide (Li₂O) and water (H₂O). The equation for this reaction would be: \[ 2LiOH \rightarrow Li₂O + H₂O \]
Make sure to check the context in which you're studying these reactions, as specific conditions might yield different products or reactions.
