Ba(OH)2+NHnCI= NaOH+MgBr2= LiOH(разложение)=

Let's balance and identify the products of the provided chemical reactions. 1. **Ba(OH)₂ + NH₄Cl**: This is a double displacement reaction. The products will be barium chloride (BaCl₂) and ammonium hydroxide (NH₄OH), which can further dissociate into NH₄⁺ and OH⁻. The balanced equation is: \[ Ba(OH)₂ + 2NH₄Cl \rightarrow BaCl₂ + 2NH₄OH \] 2. **NaOH + MgBr₂**: This is also a double displacement reaction. The products will be sodium bromide (NaBr) and magnesium hydroxide (Mg(OH)₂). The balanced equation is: \[ 2NaOH + MgBr₂ \rightarrow 2NaBr + Mg(OH)₂ \] 3. **LiOH (decomposition)**: Lithium hydroxide (LiOH) under decomposition typically does not break down into simpler components under normal conditions. However, if provided with sufficient heat, it could decompose into lithium oxide (Li₂O) and water (H₂O). The equation for this reaction would be: \[ 2LiOH \rightarrow Li₂O + H₂O \] Make sure to check the context in which you're studying these reactions, as specific conditions might yield different products or reactions.