To solve the equation \( \frac{1}{50} = \frac{x + 30}{50x + 600} \), we can cross-multiply to eliminate the fractions:
\[ 1 \cdot (50x + 600) = 50 \cdot (x + 30) \]
This simplifies to:
\[ 50x + 600 = 50x + 1500 \]
Next, to isolate the terms, subtract \( 50x \) from both sides:
\[ 600 = 1500 \]
At this point, we notice that \( 600 \) is not equal to \( 1500 \). This situation indicates that there is no solution for \( x \) that satisfies the original equation; the equation is inconsistent.
Thus, the conclusion is that there is no value of \( x \) that makes the equation true.