It looks like you have a linear expression: \(-12x - 8y + 20\). If you're preparing for university exams, here are a few things you might consider doing with this expression:
Factor the Expression: You can factor out a common factor from the first two terms: \[ -4(3x + 2y) + 20 \] or factor it in a different way if needed, or consolidate the constant term differently.
Solve for y: If you're looking to solve for y in terms of x: \[ -8y = 12x - 20 \\ y = -\frac{12}{8}x + \frac{20}{8} \\ y = -\frac{3}{2}x + \frac{5}{2} \]
Graph the Equation: If this is to be treated as an equation (e.g., setting it equal to zero), you can graph it by finding the intercepts and plotting the line.
Evaluate for Specific Values: You can evaluate this expression for specific values of \(x\) and \(y\).
Applications: Think about applications where such linear relationships might arise, such as in economics, physics, or other areas.
Let me know if you need help with a specific aspect of this expression!