Cu SOu + NaOH → Cn (OH) 2 + H CI → Ba CI2 + H2 S0 4 → Mg+ HCI →

Let's balance and identify the products for each of the reactions you provided.

1. CuSO₄ + NaOH → This reaction will result in the formation of copper(II) hydroxide and sodium sulfate. The balanced equation is: \[ CuSO₄ + 2NaOH → Cu(OH)₂ + Na₂SO₄ \] Copper(II) hydroxide, Cu(OH)₂, is a blue precipitate.

2. Cn(OH) + HCl → Assuming you meant to write "Cu(OH)₂" instead of "Cn(OH)", this reaction will form copper(II) chloride and water: \[ Cu(OH)₂ + 2HCl → CuCl₂ + 2H₂O \]

3. BaCl₂ + H₂SO₄ → This reaction will yield barium sulfate and hydrochloric acid. The balanced equation is: \[ BaCl₂ + H₂SO₄ → BaSO₄ + 2HCl \] Barium sulfate, BaSO₄, is an insoluble precipitate.

4. Mg + HCl → This reaction produces magnesium chloride and hydrogen gas. The balanced equation is: \[ Mg + 2HCl → MgCl₂ + H₂ \]

If you meant something different for "Cn(OH)", please clarify, and I can assist you further.