R-C ≡ CNa + H-OH → ин + NaOH

It seems that the equation you have provided is not balanced and contains some non-standard symbols. Let's first try to balance the equation correctly and then analyze it:

The given equation: R-C ≡ CNa + H-OH → ин + NaOH

Balancing the chemical equation: R-C ≡ CNa + H-OH → R-CN + NaOH

Now, the balanced equation indicates that an alkyne (R-C≡C-R) reacts with sodium hydroxide (NaOH) to form a nitrile (R-CN) and sodium hydroxide (NaOH).

Do you need any further clarification or assistance with this reaction?