(2x + 3)* = 3x' +12х +11.

It seems like there might be a typo in the expression you provided. I assume you meant to write:

(2x + 3) * x = 3x + 12x + 11

To solve this equation, we can first simplify the left side by distributing the x:

2x^2 + 3x = 3x + 12x + 11

Now, combine the x terms on the right side:

2x^2 + 3x = 15x + 11

Subtract 15x from both sides to get all the terms on one side:

2x^2 - 12x + 3 = 11

Now, we have a quadratic equation. We can set it equal to zero by subtracting 11 from both sides:

2x^2 - 12x - 8 = 0

Now, we can solve this quadratic equation using factoring, quadratic formula, or completing the square method. Let me know if you need help with any of those methods.