sin 2x/3 = 1

To solve the equation sin(2x/3) = 1, we need to find the values of x that satisfy this equation.

Since sin(angle) = 1 when the angle is π/2 radians or 90 degrees, we have: 2x/3 = π/2 + 2nπ for any integer n

Now, we solve for x: 2x = 3(π/2 + 2nπ) x = 3π/4 + 3nπ

Therefore, the general solution to the equation sin(2x/3) = 1 is x = 3π/4 + 3nπ for any integer n.