Решить функции

Давайте по шагам решим каждую функцию при заданных значениях переменных. Мы будем находить значения каждой функции при указанных значениях x, а затем заполнять таблицу. --- ### 1. \( y = x + 3 \) - при \(x = -7\): \( y = -7 + 3 = -4 \) - при \(x = 0\): \( y = 0 + 3 = 3 \) - при \(x = 0.5\): \( y = 0.5 + 3 = 3.5 \) - при \(x = 13\): \( y = 13 + 3 = 16 \) --- ### 2. \( y = 2x - 1 \) - при \(x = -3\): \( y = 2 \cdot (-3) - 1 = -6 - 1 = -7 \) - при \(x = 7\): \( y = 2 \cdot 7 - 1 = 14 - 1 = 13 \) - при \(x = 8.2\): \( y = 2 \cdot 8.2 - 1 = 16.4 - 1 = 15.4 \) - при \(x = -7\) (последняя строка): \( y = 2 \cdot (-7) - 1 = -14 - 1 = -15 \) --- ### 3. \( y = 5x + 4 \) - при \(x = 0\): \( y = 5 \cdot 0 + 4 = 4 \) - при \(x = -6\): \( y = 5 \cdot (-6) + 4 = -30 + 4 = -26 \) - при \(x = 1/5\): \( y = 5 \cdot 1/5 + 4 = 1 + 4 = 5 \) - при \(x = -22\) (последняя строка): \( y = 5 \cdot (-22) + 4 = -110 + 4 = -106 \) --- ### 4. \( y = -3x + 2 \) - при \(x = -5\): \( y = -3 \cdot (-5) + 2 = 15 + 2 = 17 \) - при \(x = 1/3\): \( y = -3 \cdot (1/3) + 2 = -1 + 2 = 1 \) - при \(x = 2.5\): \( y = -3 \cdot 2.5 + 2 = -7.5 + 2 = -5.5 \) - при \(x = -22\): \( y = -3 \cdot (-22) + 2 = 66 + 2 = 68 \) --- ### 5. \( y = -10x - 1 \) - при \(x = -1.5\): \( y = -10 \cdot (-1.5) - 1 = 15 - 1 = 14 \) - при \(x = -0.3\): \( y = -10 \cdot (-0.3) - 1 = 3 - 1 = 2 \) - при \(x = 4\): \( y = -10 \cdot 4 - 1 = -40 - 1 = -41 \) - при \(x = -6\): \( y = -10 \cdot (-6) - 1 = 60 - 1 = 59 \) --- ### 6. \( y = 0.5x + 5 \) - при \(x = -3\): \( y = 0.5 \cdot (-3) + 5 = -1.5 + 5 = 3.5 \) - при \(x = 4\): \( y = 0.5 \cdot 4 + 5 = 2 + 5 = 7 \) --- ### 7. \( y = \frac{2}{5}x - 3 \) - при \(x = -5\): \( y = \frac{2}{5} \cdot (-5) - 3 = -2 - 3 = -5 \) - при \(x = -7\): \( y = \frac{2}{5} \cdot (-7) - 3 = -2.8 - 3 = -5.8 \) - при \(x = 0\): \( y = 0 - 3 = -3 \) - при \(x = 2.5\): \( y = \frac{2}{5} \cdot 2.5 - 3 = 1.0 - 3 = -2 \) --- ### 8. \( y = \frac{3}{x + 2} \) - при \(x = -6\): \( y = \frac{3}{-6 + 2} = \frac{3}{-4} = -0.75 \) - при \(x = -1\): \( y = \frac{3}{-1 + 2} = \frac{3}{1} = 3 \) - при \(x = 1\): \( y = \frac{3}{1 + 2} = 1 \) - при \(x = -7\): \( y = \frac{3}{-7 + 2} = \frac{3}{-5} = -0.6 \) --- ### 9. \( y = -\frac{2}{x} - 4 \) - при \(x = -2\): \( y = -\frac{2}{-2} - 4 = 1 - 4 = -3 \) - при \(x = -1\): \( y = -\frac{2}{-1} - 4 = 2 - 4 = -2 \) - при \(x = 1\): \( y = -\frac{2}{1} - 4 = -2 - 4 = -6 \) - при \(x = -5\): \( y = -\frac{2}{-5} - 4 = 0.4 - 4 = -3.6 \) --- ### 10. \( y = x^2 - 7 \) - при \(x = -1\): \( y = (-1)^2 - 7 = 1 - 7 = -6 \) - при \(x = 2\): \( y = 4 - 7 = -3 \) - при \(x = 2\): \( y = 4 - 7 = -3 \) - при \(x = -3\): \( y = 9 - 7 = 2 \) --- Если нужно, я помогу составить заполненную таблицу целиком или более подробно объяснить любой из этапов.