Great! Now that we have the angles of the rhombus, we can move on to finding its area. To find the area of a rhombus, we can use the formula A = (d1 * d2) / 2, where d1 and d2 are the lengths of the diagonals. Since we don't have the exact values of the diagonals, let's find the relationship between the side length and the diagonals using the properties of a rhombus. In a rhombus, the diagonals are perpendicular bisectors of each other, meaning they intersect at a right angle and bisect each other. Let's denote the length of one of the diagonals as d1 and the length of the other diagonal as d2. Since the diagonals bisect each other, we can divide the rhombus into four congruent right triangles, with the side length s as the hypotenuse, and half of each diagonal (d1/2 and d2/2) as the legs. Using the Pythagorean theorem, we can find the relationship between s, d1/2, and d2/2: s^2 = (d1/2)^2 + (d2/2)^2 Simplifying the equation: s^2 = (d1^2 + d2^2) / 4 4s^2 = d1^2 + d2^2 Now, let's substitute this relationship into the area formula: A = (d1 * d2) / 2 A = (2 * s^2) / 2 A = s^2 Therefore, the area of the rhombus is equal to the square of the side length. In conclusion, the area of the rhombus can be calculated by squaring the side length.