Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №32737
А
Аноним
04 ноября 2023 21:19 · публичный вопрос
А
Аноним

Наталя та Інна купили однакові коробки чаю в пакетиках. Відомо, що одного пакетика вистачає на 2 або 3 чашки чаю. Наталі вистачило пакетиків із коробки на 41 чашку чаю, а Інні- на 58. Скільки пакетиків чаю було у коробці? Формула

Нейросеть04 ноября 2023 21:19

Let's say there were "x" tea bags in each box. According to the given information, Natalia used enough teabags for 41 cups of tea and Inna used enough teabags for 58 cups of tea.

Since each tea bag can make either 2 or 3 cups of tea, we can set up the following equation: (2 or 3) * x = 41 - (1) [for Natalia] (2 or 3) * x = 58 - (2) [for Inna]

To find the total number of tea bags, we need to find the least common multiple (LCM) of 2 and 3. The LCM of 2 and 3 is 6.

So, we can rewrite the equation as: 6 * x = 41 - (1) [for Natalia] 6 * x = 58 - (2) [for Inna]

Now we can solve for "x" using each equation.

For Natalia: 6 * x = 41 x = 41 / 6 x ≈ 6.8

For Inna: 6 * x = 58 x = 58 / 6 x ≈ 9.7

Since we can't have a fractional number of tea bags, we must round both answers to the nearest whole number.

Therefore, there were approximately 7 tea bags in Natalia's box and approximately 10 tea bags in Inna's box.

Наталя та Інна купили однакові коробки чаю в пакетиках. Відомо, що одного пакетика вистачає на 2 або 3 чашки чаю. Наталі вистачило пакетиків із коробки на 41 чашку чаю, а Інні- на 58. Скільки пакетиків чаю було у коробці? Формула
Let's say there were "x" tea bags in each box. According to the given information, Natalia used enough teabags for 41 cups of tea and Inna used enough teabags for 58 cups of tea. Since each tea bag can make either 2 or 3 cups of tea, we can set up the following equation: (2 or 3) * x = 41 - (1) [for Natalia] (2 or 3) * x = 58 - (2) [for Inna] To find the total number of tea bags, we need to find the least common multiple (LCM) of 2 and 3. The LCM of 2 and 3 is 6. So, we can rewrite the equation as: 6 * x = 41 - (1) [for Natalia] 6 * x = 58 - (2) [for Inna] Now we can solve for "x" using each equation. For Natalia: 6 * x = 41 x = 41 / 6 x ≈ 6.8 For Inna: 6 * x = 58 x = 58 / 6 x ≈ 9.7 Since we can't have a fractional number of tea bags, we must round both answers to the nearest whole number. Therefore, there were approximately 7 tea bags in Natalia's box and approximately 10 tea bags in Inna's box.