3•(a21+b167)≠0

Interpretation (assuming real or complex numbers, i.e., char ≠ 3): - The expression is 3 · (a21 + b167) ≠ 0. - Since 3 ≠ 0, this is equivalent to a21 + b167 ≠ 0. - Equivalently, a21 ≠ −b167. Note: If you’re working over a field of characteristic 3 (where 3 = 0), then 3 · (anything) = 0, so the inequality would never hold. In standard real/complex contexts, the above equivalence applies. If you want, tell me the context (e.g., are a21 and b167 entries of matrices, or variables to solve for?), and I can tailor the explanation or solve for a specific variable.