Задача Задача №3365100
А
А
(4x + 2y)^2 = (4x)^2 + 2*(4x)*(2y) + (2y)^2 = 16x^2 + 16xy + 4y^2
(1 + 4a)^3 = 1 + 3*(4a) + 3*(4a)^2 + (4a)^3 = 1 + 12a + 48a^2 + 64a^3
(x^3 + 4y)(x^3 - 4y) = (x^3)^2 - (4y)^2 = x^6 - 16y^2
(4x + 2y)^2 = (4x)^2 + 2*(4x)*(2y) + (2y)^2 = 16x^2 + 16xy + 4y^2
(1 + 4a)^3 = 1 + 3*(4a) + 3*(4a)^2 + (4a)^3 = 1 + 12a + 48a^2 + 64a^3
(x^3 + 4y)(x^3 - 4y) = (x^3)^2 - (4y)^2 = x^6 - 16y^2