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Задача Задача №3379830
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11 сентября 2025 14:54 · публичный вопрос
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Аноним

Multiply the difference between the numbers 3459 and 2451 by 2356 units. Subtract the product of the numbers 8 and 15 from the number 943. The floor length of the classroom is 12…

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Multiply the difference between the numbers 3459 and 2451 by 2356 units. Subtract the product of the numbers 8 and 15 from the number 943. The floor length of the classroom is 12 m, the width is 2 times shorter. Find the perimeter of the classroom floor. Remember how to do the opposite. Formulate the problem in reverse and solve it.

Ответ нейросети
11 сентября 2025 14:54

Here are the results with concise steps.

  1. (3459 − 2451) × 2356
  • 3459 − 2451 = 1008
  • 1008 × 2356 = 2,374,848
  • Product: 2,374,848 (in square units, if the difference is in units)
  1. 943 − (8 × 15)
  • 8 × 15 = 120
  • 943 − 120 = 823
  • Result: 823
  1. Perimeter of the classroom floor
  • Given length = 12 m, width is 2 times shorter → width = 12 / 2 = 6 m
  • Perimeter P = 2 × (length + width) = 2 × (12 + 6) = 36 m
  • Reverse check: If P = 36 m and L = 12 m, then W must satisfy 2 × (12 + W) = 36 → W = 6 m, which is consistent.

Final answers:

  • Product: 2,374,848
  • Subtraction result: 823
  • Perimeter: 36 m