x*+1 x** dx = 13 n+ 1+C 14

It looks like you’re asking for the integral of x^n with respect to x.

• If n ≠ -1: ∫ x^n dx = x^{n+1} / (n+1) + C
• If n = -1: ∫ x^{-1} dx = ∫ (1/x) dx = ln|x| + C

Reason: differentiating x^{n+1}/(n+1) gives x^n (for n ≠ -1).

If you meant a definite integral, or if n is not a constant, let me know and I’ll adjust.