Y=(x-1)2 y=0 x=3

It looks like you have a differential equation with an initial condition: dy/dx = (x − 1)^2, y(3) = 0. Steps: - Integrate: y(x) = ∫ (x − 1)^2 dx + C = (x − 1)^3 / 3 + C - Apply y(3) = 0: 0 = (3 − 1)^3 / 3 + C = 8/3 + C, so C = −8/3 - Solution: y(x) = (x − 1)^3 / 3 − 8/3 = [ (x − 1)^3 − 8 ] / 3 Equivalent form: y(x) = (x − 3)(x^2 + 3) / 3 If you meant something else by your notation, please share the exact equation and conditions.