Вопрос от Анонимного юзера 11 октября 2025 08:47

Question 1

21c2/b8•b2 /14c

Answer

I think you’re using binomial coefficients, but the grouping isn’t clear from “21c2/b8•b2 /14c”. Could you confirm the exact expression? For example, do you mean one of these?

(21C2) / (8C2) × (2) / (14C2)

If you meant that, here’s the calculation:

21C2 = 210
8C2 = 28
14C2 = 91

So the value is (210/28) × (2/91) = 7.5 × (2/91) = (15/2) × (2/91) = 15/91 ≈ 0.1648.

If you intended a different grouping (for example, 14C with a different missing parameter, or a different last binomial term), please rewrite with explicit parentheses, e.g.:

[(21C2) / (8C2)] × [2 / (14Ck)] where k is 0,1,2, etc.
(21C2) / [(8C2) × (2)] / (14Ck)

Tell me the exact expression (and which is n and k in each C(n,k)), and I’ll compute it step by step.

Question 2

21c2/b8•b2 /14c

Answer

I think you’re using binomial coefficients, but the grouping isn’t clear from “21c2/b8•b2 /14c”. Could you confirm the exact expression? For example, do you mean one of these? - (21C2) / (8C2) × (2) / (14C2) If you meant that, here’s the calculation: - 21C2 = 210 - 8C2 = 28 - 14C2 = 91 So the value is (210/28) × (2/91) = 7.5 × (2/91) = (15/2) × (2/91) = 15/91 ≈ 0.1648. If you intended a different grouping (for example, 14C with a different missing parameter, or a different last binomial term), please rewrite with explicit parentheses, e.g.: - [(21C2) / (8C2)] × [2 / (14Ck)] where k is 0,1,2, etc. - (21C2) / [(8C2) × (2)] / (14Ck) Tell me the exact expression (and which is n and k in each C(n,k)), and I’ll compute it step by step.

21c2/b8•b2 /14c

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