(1+х)^5

Using the binomial theorem: (1 + x)^5 = C(5,0) x^0 + C(5,1) x^1 + C(5,2) x^2 + C(5,3) x^3 + C(5,4) x^4 + C(5,5) x^5 = 1 + 5x + 10x^2 + 10x^3 + 5x^4 + x^5. If you’re using Cyrillic, it’s the same with х instead of x: (1 + х)^5 = 1 + 5х + 10х^2 + 10х^3 + 5х^4 + х^5.