Задача Задача №3501123
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sin(∠O) = 1/4, and in any triangle a = 2R sin A (a — side opposite angle A).
- MK = 6 is opposite ∠O, so 6 = 2R sin(∠O) = 2R · (1/4) = R/2, hence R = 12.
- OK = 8 is opposite ∠M, so sin(∠M) = OK / (2R) = 8 / (2·12) = 8/24 = 1/3.
Ответ: sin(∠M) = 1/3.