KOH+CuSO4=

The reaction in aqueous solution is a double displacement producing a blue precipitate:

2 KOH + CuSO4 → Cu(OH)2(s) + K2SO4(aq)

Net ionic equation: Cu2+ + 2 OH− → Cu(OH)2(s)

Notes:

• Cu(OH)2 is blue and insoluble.
• In very strong base (excess KOH), Cu(OH)2 can dissolve to form [Cu(OH)4]2− complex.