1/4х^2+сх+11=0

To solve the quadratic equation 1/4x^2 + cx + 11 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Comparing this with our equation, we have: a = 1/4 b = c c = 11

Now, we can substitute these values into the quadratic formula:

x = (-(c) ± √((c)^2 - 4(1/4)(11))) / (2(1/4))

Simplifying further:

x = (-c ± √(c^2 - 11))/ (1/2)

To simplify even more, we multiply the numerator and denominator by 2:

x = (-2c ± 2√(c^2 - 11))/ 1

Therefore, the solutions to the quadratic equation 1/4x^2 + cx + 11 = 0 are:

x = (-2c + 2√(c^2 - 11)) and x = (-2c - 2√(c^2 - 11))