1/4х^2+сх+11=0

To solve the equation 1/4x^2 + cx + 11 = 0, you can use the quadratic formula. The quadratic formula states that if you have an equation in the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 1/4, b = c, and c = 11. Substituting these values into the quadratic formula, we get:

x = (-(c) ± √(c^2 - 4(1/4)(11))) / (2(1/4))

Simplifying this further, we have:

x = (-c ± √(c^2 - 11)) / (1/2)

Rationalizing the denominator, we get:

x = (-c ± 2√(c^2 - 11)) / 1

So, the solutions for x are:

x = -c + 2√(c^2 - 11) x = -c - 2√(c^2 - 11)

Please note that these are the general solutions, and the value of c is not provided in the equation. To find the actual solutions, you would need to substitute the specific value of c into the above equations.