1^3 + 2^3 + 3^3 +….+99^3

Sum of cubes formula: ∑_{k=1}^n k^3 = (n(n+1)/2)^2.

For n = 99:

• n(n+1)/2 = 99·100/2 = 4950
• (4950)^2 = 24,502,500

So, 1^3 + 2^3 + ... + 99^3 = 24,502,500.