2x^2+4x+5=0

To solve the quadratic equation 2x^2 + 4x + 5 = 0, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a),

where a, b, and c are the coefficients of the quadratic equation.

In this case, a = 2, b = 4, and c = 5.

Substituting the values into the quadratic formula:

x = (-4 ± √(4^2 - 4 * 2 * 5)) / (2 * 2) x = (-4 ± √(16 - 40)) / 4 x = (-4 ± √(-24)) / 4

Since the discriminant (b^2 - 4ac) is negative, the equation has no real solutions. The solutions would be complex numbers. Hence, the quadratic equation 2x^2 + 4x + 5 = 0 has no real solutions.